405x^2+90x+5=0

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Solution for 405x^2+90x+5=0 equation: 



405x^2+90x+5=0

a = 405; b = 90; c = +5;
Δ = b2-4ac
Δ = 902-4·405·5
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-90}{810}=-1/9$

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